-4n^2+26n-13=-8-8n^2+7n

Solution for -4n^2+26n-13=-8-8n^2+7n equation:

-4n^2+26n-13=-8-8n^2+7n

We move all terms to the left:

-4n^2+26n-13-(-8-8n^2+7n)=0

We get rid of parentheses

-4n^2+8n^2-7n+26n+8-13=0

We add all the numbers together, and all the variables

4n^2+19n-5=0

a = 4; b = 19; c = -5;
Δ = b2-4ac
Δ = 192-4·4·(-5)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-21}{2*4}=\frac{-40}{8}
=-5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+21}{2*4}=\frac{2}{8}
=1/4
$